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Question 251871: Of three numbers, the 3rd is one less than the sum of the other two. It is also 8 more than twice the 2nd. The 1st is one less than 3 times the difference of the 3rd minus the 2nd. What is the largest of the three numbers?
Answer by richwmiller(17219)   (Show Source):
You can put this solution on YOUR website! let n, m and p be the three numbers.
the 3rd is one less than the sum of the other two
p=n+m-1
It is also 8 more than twice the 2nd.
p=8+2*m
The 1st is one less than 3 times the difference of the 3rd minus the 2nd.
n=3*(p-m)-1
so our three equations with three unknowns are
p=n+m-1
p=8+2*m
n=3*(p-m)-1
m = -7, n = 2, p = -6
n is the largest since n=2 and the others are negative
check
1-
p=n+m-1
-6=2-7-1
-6=2-8
-6=-6
ok
2-
p=8+2*m
-6=8+2*(-7)
-6=8-14
-6=-6
ok
3-
n=3*(p-m)-1
2=3*(-6-(-7))-1
2=3*(-6+7)-1
2=3*(1)-1
2=3-1
2=2
ok
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