SOLUTION: The perimeter of a rectangle is 30 centimeters, and the area is 54 square centimeters. Find the length and width of the rectangle. [Hint: Let w represent the width; then 15 - w r

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Question 250256: The perimeter of a rectangle is 30 centimeters, and the area is 54 square centimeters. Find the length and width of the rectangle. [Hint: Let w represent the width; then 15 - w represents the length.]
Answer by mathhub(11) About Me  (Show Source):
You can put this solution on YOUR website!
Let width = w
Therefore lengh = 15 - w
Area = width*length
=+w%2815-w%29
=+15w+-+w%5E2
It is given that area = 54
=> 54+=+15w+-+w%5E2
=> w%5E2+-+15w+%2B+54+=+0
=> w%5E2+-+6w+-+9w+%2B+54+=+0
=> w%28w-6%29+-9%28w-6%29+=+0
=> %28w-6%29%28w-9%29=0
=> w = 6 or w = 9
Therefore width is 6 and the length is 9