SOLUTION: The lesser of two consecutive even integers is 10 more than one-half the greater. Find the integers

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: The lesser of two consecutive even integers is 10 more than one-half the greater. Find the integers      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 248465: The lesser of two consecutive even integers is 10 more than one-half the greater. Find the integers
Found 2 solutions by College Student, dabanfield:
Answer by College Student(505) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = integer
Let x+2 = consecutive even integer

If the lesser of two consecutive integers is 10 more than one-half the greater, the equation becomes: x%2B10=%281%2F2%29%28x%2B2%29

Now solve for x to determine the first integer.
Then add 2 to find the consecutive even integer.
*** The solutions will result in negative integers. ***

Answer by dabanfield(803) About Me  (Show Source):
You can put this solution on YOUR website!
The lesser of two consecutive even integers is 10 more than one-half the greater. Find the integers
Let x be the smaller even integer.
Then x+2 is the next even integer.
We are given that:
x = ((1/2)*(x+2)) + 10.
Solve for x.