SOLUTION: find two consecutive odd integers such that the difference of their squares is 160.
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Question 228596
:
find two consecutive odd integers such that the difference of their squares is 160.
Answer by
rapaljer(4671)
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Let x= first odd integer
x+2 = second odd integer
(x+2)^2 - x^2 = 160
x^2 + 4x + 4 - x^2 = 160
4x+4 = 160
4x=156
x= 39
x+2= 41
Check:
41^2- 39^2
1681-1521
=160 It checks!!
Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus