SOLUTION: Find three consecutive even integers such that three times the middle integers is 10 more than the greatest
answer:x=2 the integers are 4,6,8
anyone tell me how my text
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answer:x=2 the integers are 4,6,8
anyone tell me how my text
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Question 217115: Find three consecutive even integers such that three times the middle integers is 10 more than the greatest
answer:x=2 the integers are 4,6,8
anyone tell me how my text book got this answer full break down thank you Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! Find three consecutive even integers such that three times the middle integers is 10 more than the greatest
.
Let x = smallest consecutive even integer
then
x+2 = middle of three consecutive even integers
x+4 = largest of three consecutive even integers
.
3(x+2) = (x+4) + 10
3x+6 = x+4+10
3x+6 = x+14
2x+6 = 14
2x = 8
x = 4 (smallest)
.
Middle:
x+2 = 4+2 = 6
.
Largest:
x+4 = 4+4 = 8
.
The three integers: 4,6,8
