SOLUTION: Solve: 3(x^2-3x) = 81
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Question 205851
:
Solve:
3(x^2-3x) = 81
Answer by
algebrapro18(249)
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3(x^2-3x) = 81
now we divide both sides by 3 and get
x^2-3x = 27
now subtract 27 from both sides
x^2-3x-27 = 0
now we factor. So what are the factors of -27:
1, 27
3, 9
hmm so it won't factor...so now we use the quadratic method.
where a = 1, b = -3, and c -27
so plugging in and simplifying we end up with
Now we know that 117 = 9*13 so the
=
and we
know the square root of 9 is 3 so we can pull that out and we get:
which is as simplified as this gets. If your professor wants this in decimal form it comes out to x = 8.4083 and x = -2.4083