SOLUTION: 30 people are having lunch at my house. 16 of them want salads, 16 of them prefer pasta, and 11 of them want steak. 5 say they want to have both salad and steak, and of these, 3

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: 30 people are having lunch at my house. 16 of them want salads, 16 of them prefer pasta, and 11 of them want steak. 5 say they want to have both salad and steak, and of these, 3       Log On

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Question 174556: 30 people are having lunch at my house. 16 of them want salads, 16 of them prefer pasta, and 11 of them want steak. 5 say they want to have both salad and steak, and of these, 3 want pasta as well. 5 want only steak, and 8 want only pasta. How many people want salad only?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
what you need to do is draw 3 circles that all intersect
exactly like the olympic circles
The circles represent steak, pasta, and salad
steak = 11
pasta = 16
salad = 16
The 5 who want salad and steak are the intersection
of the steak and salad circles
3 of those are in the pasta circle
The steak circle is made up of
5 want only steak
5 want steak and salad
11+-+%285%2B5%29+=+1 so,
1 wants steak and pasta
8 want only pasta
3 want pasta,steak and salad
16+-+%288+%2B+1+%2B+3%29+=+4 so,
4 want salad and pasta
3 want all the items
2 want steak and salad
16+-+%282+%2B+3+%2B+4%29+=+7 so,
7 people want salad only
(unless I goofed)