SOLUTION: find two consecutive even integhers such that the larger, added to eight times the smaller, equals 110

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Question 153780: find two consecutive even integhers such that the larger, added to eight times the smaller, equals 110
Answer by orca(409) About Me  (Show Source):
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Let the two consecutive even integers be n,n+2
As the larger, added to eight times the smaller, equals 110, we have
n + 2 + 8n = 110
Solving for n, we obtain:
9n + 2 = 110
9n = 108
n = 12
So the two consecutive even integers are 12 and 14.