SOLUTION: Sandy held a garage sale during which she charged a dime for everything, but accepted a nickel if the buyer bargained well. At the end of the day she realized she had sold all 12

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Question 131307: Sandy held a garage sale during which she charged a dime for everything, but accepted a nickel if the buyer bargained well. At the end of the day she realized she had sold all 12 items and raked in a grand total of 95 cents. She had only dimes and nickels. How many of each did she have?
Answer by solver91311(24713) About Me  (Show Source):
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Number of nickels: n
Number of dimes: d
Total number of coins: 12, so n%2Bd=12, in other words, n=12-d

Total value of n nickels is 5n cents.
Total value of d dimes is 10d cents.
Total money collected is 5n+%2B+10d=95, but since n=12-d

5%2812-d%29%2B10d=95
60-5d%2B10d=95
5d=35
d=7 and n=12-7=5

Check:
7 dimes is worth 70 cents
5 nickels is worth 25 cents
70 plus 25 is 95. Answer checks.