SOLUTION: please help me to solve this problem The sum of two numbers is 18 one number is less than twice the other find them

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Question 1186963: please help me to solve this problem

The sum of two numbers is 18 one number is less than twice the other find them

Found 2 solutions by MathLover1, greenestamps:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
let numbers be x and y
if the sum of two numbers is 18+, we have
x%2By=18..........eq.1

if one number is less than twice the other, we have
x%3C2y........ineq.2
go to
x%2By=18..........eq.1, solve for x
x=18-y
go to
x%3C2y........ineq.2, substitute x
18-y%3C2y
18%3C2y%2By
18%3C3y
6%3Cy
or
y%3E6
let say y=7, first number greater than 6
then
x=18-7
x=11
so, the numbers are: 7 and 11
you can take second number greater than 6
8 and 10
or third number greater than 6
9 and 9


Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


The problem as posted makes no sense; I don't know what the other tutor was trying to do with it....

Take ANY two numbers with a sum of 18 and one of them will be less than twice the other.

9 and 9 --> 9 is less than 2(9)=18
5 and 13 --> 5 is less than 2(13)=26
13 and 5 --> 5 is less than 2(13)=26
18 and 0 --> 0 is less than 2(18)=36
-7 and 25 --> -7 is less than 2(25)=50
...
etc.

Very probably the statement of the problem is supposed to say something like "... one number is 3 less than twice the other..."