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The ones digits of consecutive powers of the number 23 form this sequence
n 1 2 3 4 5 6 7 8 9 10
The last digit 3 9 7 1 3 9 7 1 3 9
The sequence of the last digits is periodical. The period starts from n = 1 and has the length of 4.
85 = 4*21 + 1.
Therefore, the last digit of the number
is equal to 1 : the first number of the period. ANSWER
Solved, explained and completed.