SOLUTION: A newspaper carrier has $3.80 in change he has four more quarters than dimes but five as many nickels as quarters how many coins of each type does he have

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Question 1130998: A newspaper carrier has $3.80 in change he has four more quarters than dimes but five as many nickels as quarters how many coins of each type does he have
Answer by ikleyn(52914) About Me  (Show Source):
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A newspaper carrier has $3.80 in change he has four more quarters than dimes but five highlight%28times%29 as many nickels as quarter.
How many coins of each type does he have
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Let Q be the number of quarters.

Then the number of dimes is (Q-4), and the number of nickels is 5Q.


The equation for the total is


    25Q + 10*(Q-4) + 5*(5Q) = 380     cents.


    25Q + 10Q - 40 +25Q = 380

    60Q = 380 + 40 = 420

    Q = 420/60 = 7.


Answer.  7 quarters,  5*7 = 35 nickels  and  7-4 = 3 dimes.


Check.   7*25 + 35*5 + 3*10 = 380 cents  total.   ! Correct !

Solved.