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Let x be the units digit.
Then the tens digit is (x+4), and the number is 10*(x+4) + x.
We are given that 10*(x+4) + x = x*(x+4) + 52.
It is your quadratic equation to find x.
x^2 - 7x + 12 = 0.
(x-4)*(x-3) = 0.
The equation has two roots. Both satisfy the problem's condition.
So, there are two solutions.
At x= 3 the number is 73. At x= 4 the number is 84.
Answer. There are two solutions: 73 and 84.
Solved.