SOLUTION: find three consecutive even intergers such that the sum of the smallest and twice the second is 20 more than the third
x,x+2,x+4
x=2(x+2)=(x+4)+20
Question 109125: find three consecutive even intergers such that the sum of the smallest and twice the second is 20 more than the third
x,x+2,x+4
x=2(x+2)=(x+4)+20
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find three consecutive even intergers such that the sum of the smallest and twice the second is 20 more than the third
,, is smalest integer
is the second integer, and twice the second is is the third integer
the sum of the smallest and twice the second is:
the smallest and twice the second is more than the third
now solve for :
...move to the left and the the right
..add all terms on both sides
.......divide both sides by .........SMALLEST integer
then .....second integer
and ...third integer
check:
the sum of smallest and second integer is: ........where is the third integer
