Question 1048199: consider two numbers. one of the numbers is 14 more than the other. the sum of their squares is 116. find the numbers Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! consider two numbers. one of the numbers is 14 more than the other. the sum of their squares is 116. find the numbers
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y = x + 14
y^2 + x^2 = 116
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Sub for y in the 2nd equation.
(x+14)^2 + x^2 = 116
2x^2 + 28x + 196 = 116
x^2 + 14x + 40 = 0
(x+4)*(x+10) = 0
x = -4, y = 10
x = -10, y = 4
