Question 1036600: If $30,000 is invested part at 6% and the rest at 8%, and the income from one year is $2100. How much was invested at 6%? Answer by jorel555(1290) (Show Source):
You can put this solution on YOUR website! Let n be the amount invested at 6%:
.06n+.08(30000-n)=2100
.06n-.08n+2400=2100
.02n=300
n=300/.02=15000 invested at 6%; another 15000 invested at 8%!!!!!!!!!!!!!!!