SOLUTION: Q1. Find the length of wiring needed to put two rows of coloured lights round a structure of dimensions 20m�12m.
Q2. How many dice each of side 1.8mm can fit in a box 18cm�9cm
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-> SOLUTION: Q1. Find the length of wiring needed to put two rows of coloured lights round a structure of dimensions 20m�12m.
Q2. How many dice each of side 1.8mm can fit in a box 18cm�9cm
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Question 1027664: Q1. Find the length of wiring needed to put two rows of coloured lights round a structure of dimensions 20m�12m.
Q2. How many dice each of side 1.8mm can fit in a box 18cm�9cm�1.98cm? Found 3 solutions by mananth, ikleyn, greenestamps:Answer by mananth(16949) (Show Source):
You can put this solution on YOUR website! Perimeter = 2(L+w)
=2(12+20)
=64
Two strings of lights
2*64 = 128 m
Volume of box =18cm×9cm×1.98cm = 320.76
1.8mm = 0.18 cm
Number of dice = (18*1.98*9)/0.18=1782
You can put this solution on YOUR website! .
Q2. How many dice each of side 1.8mm can fit in a box 18cm x 9cm x 1.98cm?
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The solution for problem Q2 in the post by @mananth is incorrect.
I came to bring a correct solution.
Notice that 1.8 mm = 0.18 cm.
So the formula to calculate and the answer to present to the teacher are
number of dice = = 100*50*11 = 55000. ANSWER
Probably the first thing we want to do is make the units consistent. Since the dice have edge length 1.8mm, we should change the dimensions of the box to 180mm x 90mm x 19.8mm.
Then an inexperienced student might find the volume of the box in mm^3 and divide that volume by the volume of each of the dice:
That's not a particularly difficult calculation if you use a calculator; it would be horrendous doing it by hand.
But a more experienced student (and one whose mental arithmetic is good) will recognize that each dimension of the box is an integer multiple of the length of the edge of the cube. Then finding the answer becomes much easier, using the following calculation (copied from tutor @ikleyn, to give her the credit for it):
number of dice = = 100*50*11 = 55000. ANSWER
Note that finding the answer this way not only gives you the answer of 55,000 -- it also shows you that the dice will be arranged 100 by 50 by 11 in the box.
That might be very useful information if this were a real problem....
