SOLUTION: Hi everyone, please can you help me with a maths problem: I am a odd 3 digit number, that is equal to another number multiplied by itself. the sum of my digits is 16. what number

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Question 1024877: Hi everyone, please can you help me with a maths problem: I am a odd 3 digit number, that is equal to another number multiplied by itself. the sum of my digits is 16. what number am i.
Thanks!!!

Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
An odd number times an odd number is an odd number.

An even number times an even number is an even number.

So, for a number times itself to be odd, the number
multiplied by itself to give that number must be odd.

The smallest odd number which times itself gives a three
digit number is 11x11 = 121.  The largest is 31x31 = 961.

Hey!  That's one of them!  I just noticed that the sum of the
digits of 961 is indeed 9+6+1 = 16.  

Are there any others?

Let's find out:

11x11 = 121, sum of the digits is 4, not 16.
13x13 = 169, aha! 1+6+9=16.  That's a solution!
15x15 = 225, sum of the digits is 9, not 16.
17x17 = 289, sum of the digits is 19, not 16.
19x19 = 361, sum of the digits is 10, not 16.
21x21 = 441, sum of the digits is 9, not 16.
23x23 = 529, aha! 5+2+9=16.  That's a solution!
25x25 = 625, sum of the digits is 13, not 16.
27x27 = 729, sum of the digits is 18, not 16.
29x29 = 841, sum of the digits is 13, not 16.
31x31 = 961, that's the first one I found.

So there are three such numbers 169, 529 and 961.

Edwin

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