SOLUTION: One number is 8 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 840, find the numbers
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Question 1015944: One number is 8 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 840, find the numbers
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Call the first number, x.
The second would be 8x.
The third would be x + 100.
Adding them we get
x + 8x + x+100 = 840
10x + 100 = 840
10x = 740
x = 74
8x = 592
x+100 = 174
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