Digit problems - Find the number using systems of linear equations
Problem 1
A two-digit number is 6 times the units digit. Find the number if the sum of its digit is 6.
Answer. 24.
Solution
If the decimal form of number is "ab", then
10a + b = 6b, according to the condition.
It implies 10a = 5b, or b = 2a.
The sum of the digit is 6:
a + b = 6 = a + 2a = 3a ====> a = 2; b = 4.
The number is "ab" = 24.
Problem 2
A two-digit number is 2 more than 8 times the sum of its digits.
Find the number if its tens digit is 6 more than its unit digit.
Answer. 82.
Solution
Let the decimal form of the number is "ab".
Then
10a + b = 2 + 8*(a+b) ("A two-digit number is 2 more than 8 times the sum of its digits")
10a + b = 2 + 8a + 8b,
2a = 2 + 7b. (1)
Also,
a = 6 + b (2) ("tens digit is 6 more than unit digit")
Substitute (2) into (1). You will get
12 + 2b = 2 + 7b,
10 = 5b ====> b = 2.
Then a = b+6 = 2 + 6 = 8, and you get the answer.
Problem 3
The sum of the digits of a two-digit number is 11.
If the digits are reversed, the new number is 45 less than the original number.
Find the number.
Solution
Let "ab" be the decimal presentation of the number, so "b" is the "units" digit
and "a" is the tens" digit.
Then the value of the original number is (10a+b),
while the value of the reversed digit number is (10b+a).
From the problem,
a + b = 11, (1)
10a + b = 10b + a + 45. (2)
Simplify equation (2) step by step
10a + b - 10b - a = 45
9a - 9b = 45
9(a-b) = 45
a - b = 45.
Thus we have this system of equations
a + b = 11, (3)
a - b = 5. (4)
To solve the system, add equations (3) and (4)
2a = 11 + 5 = 16, a = 16/2 = 8.
Then from (3) b = 11 -a = 11 - 8 = 3.
ANSWER. The number is 83.
CHECK. The sum of the digits is 8 + 3 = 11;
the difference of the numbers is 83 - 38 = 45. ! correct !
Problem 4
A two digit number is such that its tens digit is greater than its unit digit by 5.
If the number is 14 less than 3 times the product of its digits, find the number
Solution
Let us present the unknown number N in decimal form via its "tens" digit "t" and "ones" digit "u" N = 10*t + u.
Then the condition says
t = u + 5 (1)
10*t + u = 3*t*u - 14. (2)
It is your system of equations to solve.
From (1), substitute the expression for "t" into equation (2). You will get
10*(u+5) + u = 3*(u+5)*u - 14,
10u + 50 + u = 3u^2 + 15u - 14,
3u^2 + 4u - 64 = 0,
=
=
.
The only integer positive solution is u = 4.
Then t = u+5 = 9.
The number is 94.
My other lessons in this site for word problems on finding numbers are
- Simple and simplest word problems on finding numbers solved by different methods
- Find the number using a single linear equation
- Find the number using quadratic equation
- Find the numbers using system of equations
- Entertainment problems on finding numbers
- OVERVIEW of lessons for word problems on finding numbers
Use this file/link ALGEBRA-I - YOUR ONLINE TEXTBOOK to navigate over all topics and lessons of the online textbook ALGEBRA-I.