Lesson Digit problems - Find the number using systems of linear equations

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Digit problems - Find the number using systems of linear equations


Problem 1

A two-digit number is  6  times the units digit.  Find the number if the sum of its digit is  6.

Answer.   24.

Solution

If the decimal form of number is  "ab",  then


10a + b = 6b,   according to the condition.


It implies  10a  = 5b,   or   b = 2a.


The sum of the digit  is 6:

a + b = 6 = a + 2a = 3a  ====>  a = 2;  b = 4.


The number is  "ab" = 24.

Problem 2

A two-digit number is  2  more than  8  times the sum of its digits.
Find the number if its tens digit is  6  more than its unit digit.

Answer.   82.

Solution

Let the decimal form of the number is "ab".


Then 

10a + b = 2 + 8*(a+b)      ("A two-digit number is 2 more than 8 times the sum of its digits")

10a + b = 2 + 8a + 8b,

2a = 2 + 7b.      (1)



Also,

a = 6 + b          (2)      ("tens digit is 6 more than unit digit")



Substitute (2) into (1). You will get

12 + 2b = 2 + 7b,

10 = 5b  ====>  b = 2.


Then a = b+6 = 2 + 6 = 8,   and you get the answer.

Problem 3

The sum of the digits of a two-digit number is  11.
If the digits are reversed,  the new number is  45  less than the original number.
Find the number.

Solution

Let "ab" be the decimal presentation of the number, so "b" is the "units" digit 
and "a" is the tens" digit.


Then the value of the original number is (10a+b),
while the value of the reversed digit number is (10b+a).


From the problem,

    a + b = 11,                (1)

    10a + b = 10b + a + 45.    (2)


Simplify equation (2) step by step

    10a + b - 10b - a = 45

      9a - 9b = 45

      9(a-b) = 45

        a - b = 45.


Thus we have this system of equations

    a + b = 11,    (3)

    a - b =  5.    (4)


To solve the system, add equations (3) and (4)

    2a = 11 + 5 = 16,  a = 16/2 = 8.


Then from (3)  b = 11 -a = 11 - 8 = 3.


ANSWER.  The number is  83.


CHECK.  The sum of the digits is 8 + 3 = 11;

        the difference of the numbers is  83 - 38 = 45.   ! correct !

Problem 4

A two digit number is such that its tens digit is greater than its unit digit by  5.
If the number is  14  less than  3  times the product of its digits,  find the number

Solution

Let us present the unknown number N in decimal form via its "tens" digit "t"  and  "ones" digit "u"  N = 10*t + u.


Then the condition says

t = u + 5                   (1)
10*t + u = 3*t*u - 14.      (2)


It is your system of equations to solve.

From (1), substitute the expression for "t" into equation (2). You will get

10*(u+5) + u = 3*(u+5)*u - 14,

10u + 50 + u = 3u^2 + 15u - 14,

3u^2 + 4u - 64 = 0,

u%5B1%2C2%5D = %28-4+%2B-+sqrt%284%5E2+-+4%2A3%2A%28-64%29%29%29%2F%282%2A3%29 = %28-4+%2B-+28%29%2F6.


The only integer positive solution is u = 4.

Then   t = u+5 = 9.


The number is  94.


My other lessons in this site for word problems on finding numbers are
    - Simple and simplest word problems on finding numbers solved by different methods
    - Find the number using a single linear equation
    - Find the number using quadratic equation
    - Find the numbers using system of equations
    - Entertainment problems on finding numbers
    - OVERVIEW of lessons for word problems on finding numbers

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