Lesson Gourmet candy mixture
Algebra
->
Customizable Word Problem Solvers
->
Mixtures
-> Lesson Gourmet candy mixture
Log On
Ad:
Over 600 Algebra Word Problems at edhelper.com
Word Problems: Mixtures
Word
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Source code of 'Gourmet candy mixture'
This Lesson (Gourmet candy mixture)
was created by by
AnlytcPhil(1806)
:
View Source
,
Show
About AnlytcPhil
:
How many pounds of gourmet candy selling for $2.80 per pound should be mixed with 7 pounds of gourmet candy selling for $1.60 per pound to obtain a mixture selling for $1.96 per pound? <pre> {{{(matrix(13,1,x, pounds, of, candy, selling, for, "$2.80", per, pound, which, is, worth, "$2.80"x))}}} + {{{(matrix(15,1,7, pounds, of, candy, selling, for, "$1.60", per, pound, which, is, worth, "$1.60"7,or,"11.20"))}}} = {{{(matrix(13,1,x+7, pounds, of, candy, selling, for, "$1.96", per, pound, which, is, worth, "$1.96"(x+7)))}}} ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ $2.80x + $11.20 = $1.96(x+7) Drop the dollar marks and move the decimals two places right 280x + 1120 = 196(x+7) 280x + 1120 = 196x + 1372 Subtract 1120 from both sides: 280x = 196x + 252 Subtract 196x from both sides: 84x = 252 Divide both sides by 84 {{{(84x)/84}}} = {{{252/84}}} x = 3 Answer 3 pounds. Edwin</pre>