SOLUTION: a 20% dye solution is to be mixed with 60% dye solution to get 240L of a 50% solution. how many liters of the 20% and 60% will be needed?

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Question 995832: a 20% dye solution is to be mixed with 60% dye solution to get 240L of a 50% solution. how many liters of the 20% and 60% will be needed?
Found 2 solutions by stanbon, ikleyn:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
a 20% dye solution is to be mixed with 60% dye solution to get 240L of a 50% solution. how many liters of the 20% and 60% will be needed?
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Equation:
active + active = active
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0.20x + 0.60(240-x) = 0.50*240
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20x + 60*240 - 60x = 50*240
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-40x = -10*240
x = 240/4 = 60 L (amt. of 20% solution needed)
240-x = 180 L (amt. of 60% solution needed)
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Cheers,
Stan H.
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Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.
For solution of similar problems see the lessons
    - Solving typical word problems on mixtures for solutions   and
    - Mixture problems
in this site.