SOLUTION: A candy store two types of candy. Type A costs $6 per pound and Type B costs $10 per pound. Sarah wants to make a mixture of these weighing 10 pounds that costs $9 per pound. How m
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: A candy store two types of candy. Type A costs $6 per pound and Type B costs $10 per pound. Sarah wants to make a mixture of these weighing 10 pounds that costs $9 per pound. How m
Log On
Question 987140: A candy store two types of candy. Type A costs $6 per pound and Type B costs $10 per pound. Sarah wants to make a mixture of these weighing 10 pounds that costs $9 per pound. How many more pounds of Type B will she need in the mixture than Type A? Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! .
A=amount of Type A; B=amount of Type B
.
A+B=10 lbs
A=10lbs-B
.
$6A+$10B=$9(10)
$6(10-B)+$10B=$90
$60-$6B+$10B=$90
$4B=$30
B=7.5 She will need 7.5 pounds of Type B.
A=10lbs-B=10lbs-7.5lbs=2.5lbs She will need 2.5 pounds of Type A.
.
7.5 pounds-2.5 pounds=5 pounds
ANSWER: She will need 5 more pounds of Type B than Type A.
.
CHECK:
$6(2.5)+$10(7.5)=$9(10)
$15+$75=$90
$90=$90
