SOLUTION: how much water is to be evaporated from 20 liters of 20 percent sugar solution to get 30 percent sugar solution.

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Question 982448: how much water is to be evaporated from 20 liters of 20 percent sugar solution to get 30 percent sugar solution.
Found 2 solutions by stanbon, KMST:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
how much water is to be evaporated from 20 liters of 20 percent sugar solution to get 30 percent sugar solution.
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Equation:
water - water = water
0.80*20 - 1*x = 0.70(20-x)
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Multiply thru by 100 to get:
80*20 - 100x = 70*20 - 70x
30x = 10*20
x = (1/3)20 = 6 2/3 Liters (amt. of water to evaporate)
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Cheers,
Stan H.
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Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
This is the kind of problem that makes a chemist cry (or at least hate the fact that math teacher have little knowledge of or respect for science).

THE WRONG SOLUTION THAT A MATH TEACHER EXPECTS:
x= volume of water evaporated, in L.
The amount of sucrose in each solution is calculated by multiplying concentration times volume;
concentration used is the percentage expressed as a decimal (0.2 for 20% and 0.3 for 30%),
and the teacher does not care what units the amount of sucrose is measured in.
So, the equation is
20%2A0.2=%2820-x%29%2A0.3
Solving:
20%2A0.2=%2820-x%29%2A0.3-->4=6-0.3x-->4-6=-0.3x-->-2=-0.3x-->%28-2%29%2F%28-0.3%29=x-->highlight%28x=6.67%29

THE SCIENTIST"S (OR CHEMICAL ENGINEER'S)POINT OF VIEW:
When solution concentrations are given as percentage,
especially if it is some solid substance dissolved in water,
you would want to specify if you meant
20 grams in a total mass of 100 grams of solution, which you write as 20%(w/w),
or 20 grams in a total volume of 100 milliliters of solution, which you write as 20%(w/v),
where the "w" and the "v" refer to weight and volume respectively.
We read {w/w) as "weight in weight" and (w/v) as "weight in volume".

If someone tells me a sucrose solution's concentration is 20%,
I would assume it is 20%(w/v), with 20 g sucrose per 100 mL (100 milliliters) of solution,
and I would go to a table to find that it has a density of 1.0810 g/mL.
That means that the 100 mL of solution really have a mass of 108.1 grams,
which would make the concentration
20g%2F%22108.1+g%22=0.185= 18.5%(w/w).

A 30%(w/v) sucrose solution, with 30 g sucrose per 100 mL
has a density of 1.1270g/mL,
meaning that the weight ratio of sucrose to solution is
30g%2F%22112.7+g%22=0.266= 26.6%(w/w).

20L of 20%(w/v) sucrose solution have a mass of
%2820L%29%2A%28%221.081+kg+%2F+L%22%29=21.62kg ,
and would contain %2820L%29%2A%28%2220+kg+%2F+100+L%22%29=4kg sucrose.

If x liters of 30%(w/v) sucrose solution were to contain 4+kg sucrose, we would have
x%2A%2830%2F100%29=4--->0.3x=4--->x=4%2F0.3--->x=13.333 (rounded),
and 13.333L of 30%(w/v) sucrose solution have a mass of
%2813.333L%29%2A%28%221.127+kg+%2F+L%22%29=15.03kg (rounded).

To get to a mass of 15.03kg from a mass of 21.62kg ,
we would need to lose
21.62kg-15.03kg=6.59kg ,
and since the lost mass is water,
with an approximate density of 1.000kg/L = 1.000g/mL,
the amount of water that needs to be evaporated is 6.59L