SOLUTION: there are two different copper alloys of total weight 50 kilograms. the first contains 40%less copper than the second one. determine the percentage of copper in first alloy . if it

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Question 972639: there are two different copper alloys of total weight 50 kilograms. the first contains 40%less copper than the second one. determine the percentage of copper in first alloy . if it is known that there were 6 kg copper in first alloy and 12 kilograms in second alloy. what is the percentage of copper in second alloy?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
x of one alloy, y of the other alloy.
Let p, be percentage of copper in the "y" alloy. The "x" alloy then will have p-%2840%2F100%29p=%2860%2F100%29p percent copper.

x%2By=50, percent copper in x is 0.60p.

Determine percent of copper in the first, "x", alloy?
Not enough information for this. You only can find that the x quantity alloy has 0.6p percent copper.

%28%280.6%29p%2F100%29%2Ax=6 from the description, "there were 6 kg copper in first alloy";

%28%280.4p%29%2F100%29%2Ay=12, from the other part, "12 kilograms in second alloy"

That showed three equations in three unknown variables. Solving for x, y, p should be possible.

system%28x%2By=50%2C100%280.6p%29x=6%2C100%280.4p%29y=12%29