SOLUTION: A mixture contains one-hundred ounces of glycol and water and is twenty-eight per cent glycol. If the mixture is to be weakened to twenty per cent, how much water must be added?
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: A mixture contains one-hundred ounces of glycol and water and is twenty-eight per cent glycol. If the mixture is to be weakened to twenty per cent, how much water must be added?
Log On
Question 972607: A mixture contains one-hundred ounces of glycol and water and is twenty-eight per cent glycol. If the mixture is to be weakened to twenty per cent, how much water must be added? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! A mixture contains one-hundred ounces of glycol and water and is twenty-eight per cent glycol. If the mixture is to be weakened to twenty per cent, how much water must be added?
***
let x=amt of water to add
28%*100=20%(100+x)
28=20+.20x
0.20x=8
x=40
How much water must be added? 40 ounces
(