SOLUTION: What quantity of 10% acid solution must be mixed with 480 mL of 60% acid solution to produce 40% acid solution?
-This is what I tried:
.10x+.60(480-x)=480*.40
.10x+288-.60x=192
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-This is what I tried:
.10x+.60(480-x)=480*.40
.10x+288-.60x=192
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Question 967842: What quantity of 10% acid solution must be mixed with 480 mL of 60% acid solution to produce 40% acid solution?
-This is what I tried:
.10x+.60(480-x)=480*.40
.10x+288-.60x=192
-.5x+288=192
-.5x=-96
x=192
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