Question 967608: Farmer wants to make a 2400 lb. feed mixture that will be 14% protein.
25% will be Barley(11.7% protein).
the rest or 75 % will consist of oats(11.8% protein) and Soy meal(44.5% protein).
how much of each will he add?
the 2400 lbs. will provide .14 x 2400 = 336 lbs. of prtoein.
the 25% Barley = 600 lbs. it will provide .117 x 600 lbs= 70.20 pounds of protein.
the rest is 1800 lbs. this amount will provide @ 265.80 lbs.
this is where I am stuck.
I don't know how to set up the equation to get the amounts of each of the remaining feeds needed to provide the 265.80 lbs.
Help please.
Answer by askhari139(3)   (Show Source):
You can put this solution on YOUR website! At this point, you need to divide 1800 lb into oats and soy meal. So, let us assume that farmer adds x lb of oats. Then, the added soy meal will be 1800-x lb.
Total protein content obtained will be (x*0.118)+ ((1800-x)*0.445) which needs to be equal to the 265.80 lb that you calculated.
Therefore,
(x*0.118)+((1800-x)*0.445) = 265.80
1800* 0.445 - 265.80 = x*(0.445-0.118)
535.2 = x*0.327
Hence x = amount of oats added = 1636.69 lb
amount of soy meal = 1800-x = 163.20
CHECK:
total protein required = 0.14*2400 = 336
total protein added = 600*0.117 + 1636.69*0.118 + 163.20*0.445 = 70.2+193.13+72.624 = 335.954
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