You can put this solution on YOUR website! How many gallons of water must be added to 5 gallons of 99% Acedic Acid to dilute to 8%.
:
let w = amt of water required to do this
.99(5) = .08(w+5)
4.95 = .08w + .40
4.95 - .40 = .08w
4.55 = .08w
w = 4.55/.08
w = 56.875 gal of water
:
:
Confirm this be finding the amt of acid in each, should remain the same
.99(5) = .08(56.875 + 5)
4.95 = .08(61.875)
4.95 = 4.95