SOLUTION: Acid solution: How much water should be added to 6 gallons of pure acid to obtain a 30% solution?

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Question 96356: Acid solution: How much water should be added to 6 gallons of pure acid to obtain a 30% solution?
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
6=.3(6+X)
6=1.8+.3X
.3X=6-1.8
X=4.2/.3
X=14 GALLONS OF WATER NEEDS TO BE ADDED.
PROOF
6=.3(6+14)
6=.3*20
6=6