Question 963141: how much solution of 20% acid, must be added to a solution of 35% acid to get 60 gallons of a 25% solution? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! how much solution of 20% acid, must be added to a solution of 35% acid to get 60 gallons of a 25% solution?
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let x=amt of 20% solution must be added
60-x=amt of 35% solution must be added
amt of acid on left side=amt of acid on right side
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20%x+35%(60-x)=25%*60
.20x+21-.35x=15
.15x=6
x=40
60-x=20
amt of 20% solution must be added=40 gal.
amt of 35% solution must be added=20 gal.
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