SOLUTION: Sandy has two bags of nuts; one with 79% peanuts, and the other with 11% peanuts. To make a 7 lb bag of 49% peanuts, how much of each should Sandy use?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Sandy has two bags of nuts; one with 79% peanuts, and the other with 11% peanuts. To make a 7 lb bag of 49% peanuts, how much of each should Sandy use?       Log On

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Question 962369: Sandy has two bags of nuts; one with 79% peanuts, and the other with 11% peanuts. To make a 7 lb bag of 49% peanuts, how much of each should Sandy use?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = pounds of 79% peanuts needed
Let +b+ = pounds of 11% peanuts needed
----------------------------------------
(1) +a+%2B+b+=+7+
(2) +%28+.79a+%2B+.11b+%29+%2F+7+=+.49+
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(2) +.79a+%2B+.11b+=+.49%2A7+
(2) +79a+%2B+11b+=+343+
Multiply both sides of (1) by +11+ and
subtract (1) from (2)
(2) +79a+%2B+11b+=+343+
(1) +-11a+-+11b+=+-77+
-------------------------
+68a+=+266+
+a+=+3.9118+
and
(1) +a+%2B+b+=+7+
(1) +3.9118+%2B+b+=+7+
(1) +b+=+3.0882+
3.9118 pounds of 79% peanuts are needed
3.0882 pounds of 11% peanuts are needed
check:
(2) +%28+.79a+%2B+.11b+%29+%2F+7+=+.49+
(2) +%28+.79%2A3.9118+%2B+.11%2A3.0882+%29+%2F+7+=+.49+
(2) +%28+3.0903+%2B+.3397+%29+%2F+7+=+.49+
(2) +3.43+=+.49%2A7+
(2) +3.43+=+3.43+
OK
hope I got it