SOLUTION: An 8 cL saline solution is 20% salt. How much distilled water must you add to the saline solution in order to dilute it to a 15% saline solution?
My answer:
Volume % salt T
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My answer:
Volume % salt T
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Question 960749: An 8 cL saline solution is 20% salt. How much distilled water must you add to the saline solution in order to dilute it to a 15% saline solution?
My answer:
Volume % salt Total salt
Water X 0 0
20% 80ml 0.2 80 x 0.2 = 16
15% X + 80 0.15 0.15(x + 80) = 0.15x + 12
16 = 0.15x + 12 4 = 0.15x 0.15x = 4 x = 4/0.15 x = 26.67ml = 2.667cl
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note that 8 centiliters (cL) = 80 mililiters (mL)
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80 * .20 = 16 mL
x * .00 = .00x mL
x+80 * .15 = .15x+12 ml
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therefore
16 ml +.00x = .15x+12 mL
.15x = 4 mL
x = 4 mL / .15 = 26.666666667 which is approx 26.67 mL = 2.667 cL
