SOLUTION: A solution of 53% alcohol is to be mixed with a solution of 22% alcohol to yield 341 Liters of a 41% solution. How many Liters of 53% solution must be used?

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Question 955061: A solution of 53% alcohol is to be mixed with a solution of 22% alcohol to yield 341 Liters of a 41% solution. How many Liters of 53% solution must be used?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = liters of 53% alcohol needed
Let +b+ = liters of 22% alcohol needed
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(1) +a+%2B+b+=+341+
(2) +%28+.53a+%2B+.22b+%29+%2F+341+=+.41+
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(2) +.53a+%2B+.22b+=+139.81+
(2) +53a+%2B+22b+=+13981+
Multiply both sides of (1) by +22+
and subtract (1) from (2)
(2) +53a+%2B+22b+=+13981+
(1) +-22a+-+22b+=+-7502+
--------------------------
+31a++=+6479+
+a+=+209+
and
(1) +a+%2B+b+=+341+
(1) +209+%2B+b+=+341+
(1) +b+=+132+
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209 liters of 53% alcohol are needed
132 liters of 22% alcohol are needed
---------------------------------
check:
(2) +%28+.53%2A209+%2B+.22%2A132+%29+%2F+341+=+.41+
(2) +%28+110.77+%2B+29.04+%29+%2F+341+=+.41+
(2) +139.81+=+139.81+
OK