SOLUTION: A radiator contains 14 quarts of fluid, 35% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 40% antifreeze?
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Question 952633: A radiator contains 14 quarts of fluid, 35% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 40% antifreeze? Found 2 solutions by stanbon, josmiceli:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A radiator contains 14 quarts of fluid, 35% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 40% antifreeze?
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Equation:
alch - alch + alch = alcohol
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0.35*14 - 0.35x + 1*x = 0.40*14
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35*14 - 0 + 100x = 40*14
100x = 5*14
x = 0.7 quarts (amt of fluid to remove and replace with pure antifreeze)
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Cheers,
Stan H.
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You can put this solution on YOUR website! Let = quarts of fluid to be
drained off = quarts of antifreeze drained off
In words:
( quarts of antifreeze ) / ( total quarts ) = 40%
1.077 quarts should be drained off & replaced
with pure antifreeze
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check:
OK
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