You can put this solution on YOUR website! how many liters of a 12% salt solution must be mixed with 19 liters of a 30% salt solution to obtain a 15%salt solution
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let x=amt of 12% solution must be mixed
12%x+30%*19=15%(19+x)
.12x+5.7=2.85+.15x
0.03x=2.85
x=95
amt of 12% solution must be mixed=95 liters