SOLUTION: How many gallons of a 60% solution must be mixed with 60 gallons of 40% solution to obtain a 50% solution? 60 + y = t ( 40% of 60) + ( 60% of y ) = 50% of t 60 + y

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Question 94915: How many gallons of a 60% solution must be mixed with 60 gallons of 40% solution to obtain a 50% solution?

60 + y = t
( 40% of 60) + ( 60% of y ) = 50% of t
60 + y = t
40( 60) 60y = ( 50)t
y = 60
t = 120

60 + 60= 120
40% of 60+ 60% of 60 = 50% of 120





Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
What is your question?
Cheers,
Stan H.