SOLUTION: A 15% acid solution is to be mixed with a 35% acid solution to produce 12 ounces of a 22% acid solution. How much of the 15% acid solution is needed? Solution Let x = __ y =___

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Question 947061: A 15% acid solution is to be mixed with a 35% acid solution to produce 12 ounces of a 22% acid solution. How much of the 15% acid solution is needed?
Solution
Let x =
__ y =_______________________________
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
You can try to fit this two-part mixture problem into one single equation in one variable.

x, how much of the 15% acid to use.
12-x, the quantity of the 30% acid to use.

highlight_green%28%280.15x%2B0.3%2812-x%29%29%2F12=0.22%29
;
simplify and solve for x.
-
15x%2B30%2812-x%29=12%2A22
15x%2B30%2A12-30x=12%2A22
-15x%2B30%2A12=22%2A12
-15x=22%2A12-30%2A12
15x=30%2A12-22%2A12
15x=8%2A12
5x=8%2A4
x=32%2F5
highlight%28x=6%262%2F5%29 ounces

You can study how this would work using two variables if you want.
Mixing two concentrations for known amount of mixture