Question 942359: how man gallons of a 20% acid solution must be mixed with 6 gallon of a 30% acid solution to make a 22% solution. Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! how many gallons of a 20% acid solution must be mixed with 6 gallon of a 30% acid solution to make a 22% solution.
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let x=amt of 20% solution must be mixed
30%*6+20%x=22%(6+x)
1.8+.2x=1.32+.22x
.02x=0.48
x=24
how many gallons of a 20% acid solution must be mixed? 24
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