Question 942120: how many quarts of pure antifreeze must be added to 6 quarts of a 30% antifreeze solution to obtain a 60% antifreeze solution? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! x = quarts of pure antifreeze
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0.30*6 + 1.00x = 0.60*(x + 6)
0.30*6 + x = 0.60x + 0.60*6
x - 0.60x = 0.60*6 - 0.30*6
0.40x = 0.60*6 - 0.30*6
x = (0.60*6 - 0.30*6)/0.40
x = 4.5
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