SOLUTION: Ali has 20 gallons of 20% sulfuric acid solution. How much 100% sulfuric acid solution must add to make a solution that is steady 50% sulfuric acid.
Question 936125: Ali has 20 gallons of 20% sulfuric acid solution. How much 100% sulfuric acid solution must add to make a solution that is steady 50% sulfuric acid. Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! let y = the number of gallons of 100% acid solution that you have to add to get a 50% acid solution.
you have 20 gallons of 20% acid solution.
your equation will be:
.2 * 20 + y = .5 * (20 + y)
20 + y is the total amount of gallons of solution that you will have when you are done.
simplify this equation to get:
4 + y = 10 + .5 * y
subtract .5 * y from both sides of this equation and subtract 4 from both sides of this equation to get:
y - .5 * y = 10 - 4
simplify to get:
.5 * y = 6
divide both sides of this equation by .5 to get:
y = 12
you will need 12 gallons of 100% acid solution added to 20 gallons of 20% acid solution to get 32 gallons of 50% acid.
the number of gallons of pure acid in the new solution will be .2 * 20 + 12 which is equal to 4 + 12 = 16
16 / 32 = 50%
numbers look good.
your solution is that you will need to add 12 gallons of 100% sulfuric acid to 20 gallons of 20% sulfuric acid to make 32 gallons of 50% sulfuric acid.
