Question 928603: Please help me solve this problem.
I have 8 gallons of a mixed fuel. It contains 93% Methanol and 7% oil. I need to add 8% Nitro to this current blend. The new mixture will be 85% Methanol, 8% Nitro and 7% oil. How can I go about making this new blend and keep it to an even amount of gallons?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! I have 8 gallons of a mixed fuel. It contains 93% Methanol and 7% oil. I need to add 8% Nitro to this current blend.
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The new mixture will be 85% Methanol, 8% Nitro and 7% oil.
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How can I go about making this new blend and keep it to an even amount of gallons?
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Start::
Meth:: 0.93*8 = 7.44 gallons of Meth
Oil:: 0,07*8 = 0.56 gallons of Oil
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Adding 0.8x nitro
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Final:::
Meth:: 7.44 = 0.85*(8+x)
7.44 = 0.85*8 + 0.85x
0.85x = 0.64
x = 0.75 gallons (amt. of Nitro to add)
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Note:: The resulting mixture will not have 7% oil because
you did not adjust the original amount of oil.
The resulting mixture will not have 8% Nitro. Your 8%
nitro has been dilluted by the Meth and oil.
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Cheers,
Stan H.
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