SOLUTION: how many liters of a 25% chemical solution must be added to 60 liters of a 50% solution to get a 30% solution? thank you very much if you can help

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Question 927999: how many liters of a 25% chemical solution must be added to 60 liters of a 50% solution to get a 30% solution?
thank you very much if you can help

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website!
This is how the solution works:
http://www.algebra.com/my/Two-Part-Mixture-with-one-material-quantity-unknown.lesson?content_action=show_dev
http://www.algebra.com/my/Two-Part-Mixture-with-one-material-quantity-unknown.lesson?content_action=show_dev

Answer by MathTherapy(10552) (Show Source):
You can put this solution on YOUR website!

how many liters of a 25% chemical solution must be added to 60 liters of a 50% solution to get a 30% solution?
thank you very much if you can help

Let amount of 25% solution to be mixed, be T
Then we get: .25T + .5(60) = .3(T + 60)
.25T + 30 = .3T + 18
.25T - .3T = 18 � 30
- .05T = - 12
T, or amount of 25% solution to mix = , or L
You can do the check!!
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