SOLUTION: how many milliliters of pure water must be added to 60 milliliters of a 20 percent salt solution to make a 12percent salt solution?

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Question 922696: how many milliliters of pure water must be added to 60 milliliters of a 20 percent salt solution to make a 12percent salt solution?

Found 2 solutions by lwsshak3, srinivas.g:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
how many milliliters of pure water must be added to 60 milliliters of a 20 percent salt solution to make a 12percent salt solution?
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let x=amt of pure water to be added
20%*60=12%(60+x)
12=7.2+.12x
.12x=4.8
x=40
amt of pure water to be added=40 milliliters

Answer by srinivas.g(540) About Me  (Show Source):
You can put this solution on YOUR website!
INitially we have 60 millilitres of solution with 20 % salt
so quantity of salt in the solution = 20% of 60 milliliters
=+%2820%2F100%29%2A60
=%2820%2F5%29%2A3
=4%2A3
= 12+ millilitres
let assume v milliliters of pure water is added to the salt solution
so total quantity of salt solution now becomes 60 +v millilitres
quantity of salt after adding water is 12 % of (60+v) millilitres
but quantity of salt in the solution is remains same even after adding water to the salt solution
so 12 = 12 % of (60+v)
+12+=+%2812%2F100%29%2A%2860%2Bv%29+
multiply with %28100%2F12%29 on both sides
+12%2A%28100%2F12%29+=+%2812%2F100%29%2A%2860%2Bv%29%2A%28100%2F12%29
+100=60%2Bv
subtract 60 on both sides
100-60+=60%2Bv-60
40 =v
so v= 40 millilitres
result : quantity of water added = 40 millilitres