SOLUTION: how many pounds of candy that sells for $0.75 per pound must be mixed with candy that sells for $1.25 per pound in order to obtain 9 pounds of a mixture that should sell for $0.96

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: how many pounds of candy that sells for $0.75 per pound must be mixed with candy that sells for $1.25 per pound in order to obtain 9 pounds of a mixture that should sell for $0.96       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 912580: how many pounds of candy that sells for $0.75 per pound must be mixed with candy that sells for $1.25 per pound in order to obtain 9 pounds of a mixture that should sell for $0.96 per pound

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
x is the amount of the $1.25
1.25x + .75(9lb - x) = .96(9lb)
x = .21(9lb)/.50, the amount of the $1.25
9lb-xthe amount of the .75cent