SOLUTION: 15 liter of solution contain 40% of sulphuric acid it mixed with 25 liter of solution containing 60% of acid Find the percentage of water in that solution
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Question 910305: 15 liter of solution contain 40% of sulphuric acid it mixed with 25 liter of solution containing 60% of acid Find the percentage of water in that solution Found 2 solutions by Alan3354, JoelSchwartz:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! 15 liter of solution contain 40% of sulphuric acid it mixed with 25 liter of solution containing 60% of acid Find the percentage of water in tat solution
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15*40 + 25*60 = 40*C (C = %age)
You can put this solution on YOUR website! .6*15+25*.4
9+10=19 liters of water that is in 40 liters of solution
x=rate of water in solution
40x=19
x=19/40
x=.475
40*.475=19
The percentage is forty seven point five percent.
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