SOLUTION: A merchant mixed 10 lb of a cinnamon tea with 6 lb of spice tea. The 16-pound mixture cost $38. A second mixture included 16 lb of the cinnamon tea and 6 lb of the spice tea. The 2

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: A merchant mixed 10 lb of a cinnamon tea with 6 lb of spice tea. The 16-pound mixture cost $38. A second mixture included 16 lb of the cinnamon tea and 6 lb of the spice tea. The 2      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 909734: A merchant mixed 10 lb of a cinnamon tea with 6 lb of spice tea. The 16-pound mixture cost $38. A second mixture included 16 lb of the cinnamon tea and 6 lb of the spice tea. The 22-pound mixture cost $50. Find the cost per pound of the cinnamon tea and of the spice tea.
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Let c = price for the cinnamon tea
Let s = price for the spice tea
Prices are dollars per pound

Account for the costs of the mixtures.

Initial system:system%2810c%2B6s=38%2C16c%2B6s=50%29
Simplification of system: highlight_green%28system%285c%2B3s=19%2C8c%2B3s=25%29%29

Perfectly ready for using Elimination Method to start.
Solve for c, and then s.