SOLUTION: How much quantity each of pure tin and iron must be added to 600 kilograms of an alloy containing 20% tin and 40% iron to make an alloy which is 25% tin and 50% iron?
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Question 907669: How much quantity each of pure tin and iron must be added to 600 kilograms of an alloy containing 20% tin and 40% iron to make an alloy which is 25% tin and 50% iron? Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! .20*600=600/5=120 kilos of tin we want .25 or 1/4 or 25%
.40*600=240 kilos of iron we want 50% or .5 or 1/2
(1)
(2)
(a + 120 ) / ( a + b + 600 ) = .25,
( b + 240 ) / ( a + b + 600 ) = .50
a=120 tin
b=240 iron
240/960=1/4
480/960=1/2
