SOLUTION: A metallurgist has one alloy containing 21% copper and another containing 60% copper. How many pounds of each alloy must he use to make 54 pounds of a third alloy containing 27% co
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Question 905035: A metallurgist has one alloy containing 21% copper and another containing 60% copper. How many pounds of each alloy must he use to make 54 pounds of a third alloy containing 27% copper? Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! a+b=54,
21*a+60*b=27*54
a=54-b
21*(54-b)+60*b=1458
1134-21b+60*b=1458
39*b=324
b=8.30769231
a=54-b
a=45.6923077 lb. at 21% b=8.30769231 lb. at 60%
check
21*45.6923077+60*8.30769231=27*54
959.538462+498.461538=1458
1458.0=1458
ok
