SOLUTION: 110 gallons of a solution is 5% alcohol, How many gallons of water must be removed in order to have a solution of 8% alcohol
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Question 902722
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110 gallons of a solution is 5% alcohol, How many gallons of water must be removed in order to have a solution of 8% alcohol
Answer by
ewatrrr(24785)
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water = water
.95(110G) - x = .92(110G - x)
.03(110G)/.08 = x, gallons of water to remove